A car having an initial speed of 16 meters per second is uniformly brought to rest in 4.0 seconds. How far does the car travel during this 4.0 second interval

Let d is the distance covered by the car

Given vi = 16, vf = 0, t = 4

Byusing the following formula we can calculate the acceleration;

vf - vi = at

a = vf - vi / t

=0 - 16 / 4

a = - 4m/s²

Now use this formula to calculate distance

d = 1/2at ² + vit

=1/2 (-4) (4) ² + 16 (4)

=-32 + 64

d = 32 m

So, the car travels 32m during this 4 second interval.