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13 June, 01:56

Charge Q = + 4.00 mC is distributed uniformly over the volume of an insulating sphere that has radius R = 5.00 cm. What is the potential difference between the center of the sphere and the surface of the sphere?

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  1. 13 June, 02:20
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    3.6 x 10^8 V

    Explanation:

    Q = 4 m C = 4 x 10^-3 C

    r = 5 cm = 0.05 m

    The formula for the potential at the surface is

    Vs = K Q / r = (9 x 10^9 x 4 x 10^-3) / 0.05 = 7.2 x 10^8 V

    The formula for the potential at the centre is

    Vc = 3/2 Vs

    Vc = 1.5 x 7.2 x 10^8 V = 10.8 x 10^8 V

    The difference in potential is

    V = Vc - Vs = 10.8 x 10^8 - 7.2 x 10^8 = 3.6 x 10^8 V
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