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18 April, 12:12

A balloon filled with helium gas at 20°C occupies 4.91 L at 1.00 atm. The balloon is immersed in liquid nitrogen at - 196°C, while the pressure is raised to 5.20 atm. What is the volume of the balloon in the liquid nitrogen?

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  1. 18 April, 12:28
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    V = 0.248 L

    Explanation:

    To do this, use the following equation:

    P1*V1/T1 = P2*V2/T2

    This equation is used to find a relation between two differents conditions of a same gas, which is this case. From this equation we can solve for V2.

    Solving for V2:

    V2 = P1*V1*T2/T1*P2

    Temperature must be at Kelvin, so, we have to sum the temperature 273 to convert it in K.

    Replacing the data we have:

    V2 = 1 * 4.91 * (-196+273) / 5.2 * (20+273)

    V2 = 378.07 / 1523.6

    V2 = 0.248 L
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