Find the product of 30--√ and 610--√. Express it in standard form (i.

e., ab√). Give the value of a followed by the value of b separated by a comma.

Question

Tramp

Physics

19 October, 08:40

Find the product of 30--√ and 610--√. Express it in standard form (i.

e., ab√). Give the value of a followed by the value of b separated by a comma.

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Answers (1)

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Abril Davila · Answer 1

The product of √30 and √610 is 10√183.

√30 = √ (2*3*5)

and √610 = √ (2*5*61

Since 61 can't be factorised further.

Therefore, the value of √30*√610 is

= √ (2*3*5*2*5*61)

= 2*5*√ (3*61)

=10√183

Find the product of 30--√ and 610--√. Express it in standard form (i.e., ab√). Give the value of a followed by the value of b separated by a comma.

Find the product of 30--√ and 610--√. Express it in standard form (i.

e., ab√). Give the value of a followed by the value of b separated by a comma.