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28 August, 05:27

A block weighing 10 newtons is resting on a plane inclined 30° to the horizontal. What is the magnitude of the normal force acting on the block? Round your answer to the nearest whole number.

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  1. 28 August, 05:52
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    Magnitude of normal force acting on the block is 7 N

    Explanation:

    10N = 1.02kg

    Mass of the block = m = 1.02 kg

    Angle of incline Θ = 30°

    Normal force acting on the block = N

    From the free body diagram,

    N = mgCos Θ

    N = (1.02) (9.81) Cos (30)

    N = 8.66 N

    Rounding off to nearest whole number,

    N = 7 N

    Magnitude of normal force acting on the block = 7 N
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