W, the turntable stops rotating, and the ladybug and the gentleman bug move to opposite edges of the outer rim. the gentleman bug has not watched his weight and is much more massive. the turntable then begins rotating ever more rapidly. who will fall off first? (assume non-zero frictional force and the same coefficients of friction for both bugs.)

Question

Alvin Dunn

Physics

17 September, 12:07

W, the turntable stops rotating, and the ladybug and the gentleman bug move to opposite edges of the outer rim. the gentleman bug has not watched his weight and is much more massive. the turntable then begins rotating ever more rapidly. who will fall off first? (assume non-zero frictional force and the same coefficients of friction for both bugs.)

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Bernie · Answer 1

The ladybug will fall off first because she is lighter than the gentleman bug.

This is because the inertia (tendency to remain at rest) is affected by weight. The more a body has weight the more its inertia force is high. The opposite is also true.