A hydraulic lift consists of two pistons that connect to each other by an incompressible fluid. If one piston has an area of 0.15 m^2 and the other an area of 6.0 m^2, how large a mass can be raised by a force of 130 N exerted on the smaller piston?

Question

Layla Pierce

Physics

26 August, 22:36

A hydraulic lift consists of two pistons that connect to each other by an incompressible fluid. If one piston has an area of 0.15 m^2 and the other an area of 6.0 m^2, how large a mass can be raised by a force of 130 N exerted on the smaller piston?

+3

Answers (1)

Know the Answer?

Peck · Answer 1

You have:

A1 = 0.15 m²

A2=6.0 m²

F1=130.0 N

To solve this problem you must use the pressure formula, as below:

P1=P2

F1/A1=F2/A2

Then, you have:

m2=A2xF1/A1xg

g=9.81 m/s² (This is the acceleration of gravity)

When you substitute the values in m2=A2xF1/A1xg, you obtain:

m2 = (0.60 m² x 130.0 N) / (0.15 m² x 9.81 m/s²)

The answer is:

m2=530 Kg