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11 February, 02:49

1. A drop of oil of volume 10-10 m spreads out on water to

make a circular film of radius 10 m. what is the thickness

of the film?

+4
Answers (1)
  1. 11 February, 02:57
    0
    318.3 nm

    Explanation:

    We approximate the circular film as a cylinder of height h and radius, r. Its volume V = πr²h. Since this volume equals the volume of the oil drop, the height of the circular film is thus h = V/πr²

    V = 10⁻¹⁰ m³ and r = 10 m

    Substituting into h, we have

    h = 10⁻¹⁰ m³/π (10) ²

    = 0.3183 * 10⁻¹² m

    = 3183 * 10⁻⁹ m

    = 318.3 nm
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