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11 June, 13:35

A person slaps her leg with her hand, which results in her hand coming to rest in a time interval of 2.75 ms2.75 ms from an initial speed of 4.75 m/s4.75 m/s. What is the magnitude of the average contact force exerted on the leg, assuming the total mass of the hand and the forearm to be 1.55 kg1.55 kg?

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  1. 11 June, 13:40
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    2677.3 N

    Explanation:

    v₀ = initial speed of the hand = 4.75 m/s

    v = final speed of the hand = 0 m/s

    m = Total mass of hand and forearm = 1.55 kg

    t = time interval for hand to come to rest = 2.75 ms = 0.00275 s

    F = Force applied on the leg

    Using Impulse-change in momentum equation

    F t = m (v - v₀)

    F (0.00275) = (1.55) (0 - 4.75)

    F = - 2677.3 N

    magnitude of force = 2677.3 N
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