Ask Question
11 July, 11:24

A trap-jaw ant snaps its mandibles shut at very high speed, good for catching small prey. But these ants also slam their mandibles into the ground; the resulting force can launch the ant into the air for a quick escape. If a 12 mg ant hits the ground with an average force of 47 mN for a time of 0.13 ms, at what speed will it leave the ground?

+1
Answers (1)
  1. 11 July, 11:26
    0
    FInal speed (v) = 0.509 m/s (Approx)

    Explanation:

    Given:

    Mass of ant (m) = 12 mg

    Force (f) = 47 N

    Time taken (t) = 0.13 ms

    Find:

    FInal speed (v) = ?

    Computation:

    Initial velocity (u) = 0

    Impulse = change in momentum

    Force * TIme = change in momentum

    47 * 0.13 = mv - mu

    6.11 = 12 (V)

    FInal speed (v) = 0.509 m/s (Approx)
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A trap-jaw ant snaps its mandibles shut at very high speed, good for catching small prey. But these ants also slam their mandibles into the ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers