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9 March, 17:09

The rate constant for the reaction is 0.230 M - 1 ⋅ s - 1 0.230 M-1⋅s-1 at 200 ∘ C. 200 ∘C. A ⟶ products A⟶products If the initial concentration of A A is 0.00290 M, 0.00290 M, what will be the concentration after 155 s?

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  1. 9 March, 17:25
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    The concentration after 155 s = 0.00263 M

    Explanation:

    From the units of the reactions rate constant, K = 0.230 M⁻¹s⁻¹, it is evident that the reaction is second order with respect to the reactant A.

    Let C = concentration of A At any time

    And C₀ = initial concentration of A = 0.00290 M

    dC/dt = - KC²

    dC/C² = - kdt

    C⁻² dC = - k dt

    ∫ C⁻² dC = - k ∫ dt

    Integrating the left hand side from C₀ to C and the right hand side from 0 to t

    - (C⁻¹ - C₀⁻¹) = - kt

    (C⁻¹ - C₀⁻¹) = kt

    (1/C) - (1/C₀) = kt

    t = 155 s, C₀ = 0.00290 M, k = 0.230 M⁻¹s⁻¹

    (1/C) - (1/0.0029) = 0.23 * 155

    (1/C) = 35.65 + 344.83 = 380.478

    C = 1/380.478 = 0.00263 M
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