Ask Question
27 December, 05:18

A man weighing 750 n and a woman weighing 500 n have the same momentum. what is the ratio of the man's kinetic energy km to that of the woman kw?

+3
Answers (1)
  1. 27 December, 05:32
    0
    Because weight W = M g, the ratio of weights equals the ratio of masses.

    (M_m g) / (M_w g) = [ (p^2 Man) / (2 K_man) ] / [ (p^2 Woman) / (2 K_woman)

    but p's are equal, so

    K_m/K_m = (M_w g) / (M_m g) = W_woman / W_man = 450/680 = 0.662
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A man weighing 750 n and a woman weighing 500 n have the same momentum. what is the ratio of the man's kinetic energy km to that of the ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers