Calculate the specific

heat capacity of substance having mass 5 kg whose

temperature increase from 15°C to 25°C by the supply of

19 KJ

Answer: c = 0.38 J / g °C

Explanation: Use the equation Q = mcΔT and derive to solve for c.

c = Q / mΔT

First convert 19 KJ to joules

19 kJ x 1000 J / 1 kJ = 19000 J

Then convert 5 kg to grams

5 kg x 1000 g / 1 kg = 5000 g

After that substitute the following variables into the equation.

c = 19000 J / 5000 g (25 - 15) = 0.38 J / g°C