You throw a ball downward from a window at a speed of 2.0m/s. How far has it fallen in 3 seconds?

Let's just assume that you throw the ball with an initial speed of 2 m/s instead of dropping it like free falling.

a=9.81 m/s^2

Vi = 2 m/s

t = 3 x

we use the formula

d = (Vi) (t) + (1/2) (a) (t) ^2

d = (2) (3) + (1/2) (9.81) (9)

d=50.145 m