A car travels along a straight line at a constant speed of 56.0 mi/h for a distance d and then another distance d in the same direction at another constant speed. The average velocity for the entire trip is 33.5 mi/h. (a) What is the constant speed with which the car moved during the second distance d?
I started out with Vxavg = (Vxi+Vxf) / 2 and came out to 11 and it was wrong. If anyone has a good website I can use to learn physics it would be much appreciated.
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