Ask Question
10 July, 03:01

A ball is thrown straight up and reaches a maximum height of 35m. Using 9.8m/s squared as gravity, what was the initial speed of the ball?

+3
Answers (1)
  1. 10 July, 03:29
    0
    26.2 m/s

    Explanation:

    Given:

    v = 0 m/s

    Δy = 35 m

    a = - 9.8 m/s²

    Find: v₀

    v² = v₀² + 2aΔy

    (0 m/s) ² = v₀² + 2 (-9.8 m/s²) (35 m)

    v₀ = 26.2 m/s
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A ball is thrown straight up and reaches a maximum height of 35m. Using 9.8m/s squared as gravity, what was the initial speed of the ball? ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers