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22 June, 16:09

Using Newton's Version of Kepler's Third Law II The Sun orbits the center of the Milky Way Galaxy every 230 million years at a distance of 28,000 light-years. Use these facts to determine the mass of the galaxy. (As we'll discuss in Chapter Dark Matter, Dark Energy, and the Fate of the Universe, this calculation actually tells us only the mass of the galaxy within the Sun's orbit.) M = solar billion years

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  1. 22 June, 16:14
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    The mass of the galaxy is 2.096 * 10⁴¹ kg

    Explanation:

    Newton's Version of Kepler's Third law of motion II is:

    p² = 4π² a³ / G (M + m) (1)

    where

    p is the orbital period a is the average distance between the sun and the galactic centre G is the universal gravitational constant M is the mass of the galaxy m is the mass of the sun

    Step 1:

    The orbital period of the sun around the galaxy is:

    p = 230*10⁶ years * (3.15*10⁷ s / 1 year)

    p = 7.25 * 10¹⁵ s

    Step 2:

    The average distance between the sun and the galactic centre is:

    a = 28000 light-years * (9.46*10¹⁵ m / 1 light-year)

    a = 2.65*10²⁰ m

    Step 3:

    Substitute the values of p and a into equation (1):

    Rearranging equation (1) to make M the subject of the formula, we get:

    M = (4π² a³ / G p²) - m

    M = (4π² (2.65*10²⁰ m) ³ / (6.67*10⁻¹¹ m) (7.25 * 10¹⁵ s) ²) - 1.9891 * 10³⁰ kg

    M = 2.096 * 10⁴¹ kg

    Therefore, the mass of the galaxy is 2.096 * 10⁴¹ kg
  2. 22 June, 16:27
    0
    mass of the galaxy = 1.05 * 10^11 solar masses

    Explanation:

    According to Kepler's third law, A^3 = P^2

    Where A = Average distance of a planet from the sun, in AU

    And P = The time taken by the planet to orbit the sun, in years.

    Newton's modification to Kepler's third law applies to any two objects orbiting a common mass

    According to Newton, M1 + M2 = (A^3) / (P^2)

    Where M1 and M2 are the masses of the two objects in Solar mass

    From the question,

    Let M1 = the mass of the sun

    and M2 = the mass of the milky way galaxy

    Distance, A = 28,000 light years

    1 light year = 63241.1 AU

    A = 28000 * 63241.1

    A = 1,770,750,800 AU

    Time taken for the orbit, P = 230,000,000 years

    M1 = 1 solar mass

    M2 = ?

    Using M1 + M2 = (A^3) / (P^2)

    1 + M2 = (1770750800^3) / (230,000,000^2)

    1 + M2 = 1.05 * 10^11

    M2 = (1.05 * 10^11) - 1

    M2 = 1.05 * 10^11 solar masses
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