Sources A and B emit long-range radio waves of wavelength 360 m, with the phase of the emission from A ahead of that from source B by 90°. The distance rA from A to a detector is greater than the corresponding distance rB from B by 150 m. What is the magnitude of the phase difference at the detector?

Question

Donavan Mckinney

Physics

21 July, 17:09

Sources A and B emit long-range radio waves of wavelength 360 m, with the phase of the emission from A ahead of that from source B by 90°. The distance rA from A to a detector is greater than the corresponding distance rB from B by 150 m. What is the magnitude of the phase difference at the detector?

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Charles Yang · Answer 1

Answer: The phase difference is 60° with source B ahead

Explanation: Considering the waves A and B emited with an initial phase difference of 90° and also we must take into account the distance to the detector, in this case the distace rB is shorter 150 m than rA.

Considering the wavelength of 360 m a phase difference of 90° is equal to 90 m in distance, so source A is ahead this path but the distance to the detector is larger so the difference that both can reach the detector is: 150m - 90m = 60 m it is equivalent to 60° in phase each other wave of arriving to the detector. The wave B is ahead.