An object is dropped from a height h. during the final second of its fall, it traverses a distance of 41.2 m. what was h?

Question

Hillary

Physics

19 December, 21:57

An object is dropped from a height h. during the final second of its fall, it traverses a distance of 41.2 m. what was h?

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Answers (1)

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Austin Stein · Answer 1

41.2 = h-1/2g (t-1) ^2

{-h = - 1/2gt^2-1/2g+g*t-41.2

{h = 1/2gt^2

summing them up

0 = - 1/2g+g*t-41.2

41.2 + 4.9 = g*t

t = 46.1/9.8 = 4.70 sec

h = 1/2gt^2 = 4.9 * (4.70^2) = 108.241 m