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17 October, 03:04

The rubidium isotope 87Rb is a β emitter that has a half-life of 4.9 ✕ 1010 y that decays into 87Sr. It is used to determine the age of rocks and fossils. Rocks containing the fossils of early animal have a ratio of 87Sr to 87Rb of 0.0040. Assuming that there was no 87Sr present when the rocks were formed, calculate the age of the fossils.

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  1. 17 October, 03:14
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    t = 39.04 1010 year

    Explanation:

    This is a nuclear disintegration exercise that is governed by the equation.

    N = N0 e (-lam t)

    The average life time is related to nuclear activity

    T ½ = ln 2 / lam

    Let's use these two equations for exercise, let's start by finding nuclear activity

    Lam = ln 2 / T ½

    Lam = ln 2 / 4.9 10 10

    Lam = 0.14146 10-10 y-1

    They tell us that the relationship atoms

    No / N = 0.0040

    Let's look

    No / N = 1/0040

    N/No = 250

    Let's calculate the time

    (-lam t) = ln (N / No)

    , t = - 1 / lam ln (n / No)

    t = - 1 / 0.14146 10-10 ln (250)

    t = 39.04 1010 year
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