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24 January, 10:12

9. A radioisotope has a half-life of 4.50 min and an initial decay rate of 8400 Bq. What will be

the decay rate after 18.0 min?

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Answers (1)
  1. 24 January, 10:33
    0
    525 Bq

    Explanation:

    The decay rate is directly proportional to the amount of radioisotope, so we can use the half-life equation:

    A = A₀ (½) ^ (t / T)

    A is the final amount

    A₀ is the initial amount,

    t is the time,

    T is the half life

    A = (8400 Bq) (½) ^ (18.0 min / 4.50 min)

    A = (8400 Bq) (½) ^4

    A = (8400 Bq) (1/16)

    A = 525 Bq
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