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4 July, 02:41

A mass M = 1.4 kg is hanging from a long string of length L-20.8 m and total mass mi = 13 kg. A student gives the mass a quick horizontal shake to set up a wave which travels upwards along the string 25% Part (a) What is the speed of the wave at the bottom of the string, in meters per second? 25% Part (b) Express the tension of the chain at a height y above the bottom in terms of M, m, and g 25% Part (c) What is the speed of the wave, in meters per second, at the top of the string?

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  1. 4 July, 02:48
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    a. v = 4.68 m/s²

    b. T₂ = 141.12 N

    c. v = 15.02 m/s²

    Explanation:

    Given:

    M = 1.4 kg, L = 20.8m, mi=13 kg

    a.

    Using the equations of kinetic energy and the spring potential

    Uk = Ek

    ¹/₂ * T * d = ¹/₂ * m * v ²

    T₁ = M * g = 1.4 kg * 9.8 m/s² = 13.72 N

    T₂ = (M + mi) * g = (1.4 kg + 13 kg) * 9.8 m/s² = 141.12 N

    a. the speed at the bottom

    v = √[ (T * d) / m] = √ 13.72 N * 20.8 m / 13 kg

    v = 4.68 m/s²

    b. the tension of the chain

    T₂ = (M + mi) * g = (1.4 kg + 13 kg) * 9.8 m/s² = 141.12 N

    c. the speed at the top of the spring

    v = √[ (T * d) / m] = √ 141.12 N * 20.8 m / 13 kg

    v = 15.02 m/s²
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