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21 January, 01:13

To what temperature would you have to heat a brass rod for it to be 1.8 % longer than it is at 30 ∘c?

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  1. 21 January, 01:41
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    In physics, certain metals elongate when it is heated. This is a consequence of the expansion of the molecules present in a metal tube, for example. This elongation is described by the equation:

    ΔL = L0*α*ΔT, where

    ΔL is the elongation. In other words, this is the difference between the original length and the elongated length.

    L0 is the original leng

    α is the coefficient of linear expansion. This is an empirical data for specific kind of materials. For brass, α = 18.9 x 10^6/°C

    ΔT is the change in temperature

    Rearranging the equation,

    ΔL/L0 = α*ΔT, where ΔL/L0 is the percentage of length expansion which is equal to 0.018 (1.8^%)

    0.018 = (18.9 x 10^-6) (T-30)

    T = 982.4°C
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