A cylindrical capacitor is made of two thin-walled concentric cylinders. The inner cylinder has radius 8 mm, and the outer one a radius 11 mm. The common length of the cylinders is 152 m. What is the potential energy stored in this capacitor when a potential difference 8 V is applied between the inner and outer cylinder? (k = 1/4∗π∗ϵ0=8.99109N⋅m2/C2) A cylindrical capacitor is made of two thin-walled concentric cylinders. The inner cylinder has radius 8, and the outer one a radius 11. The common length of the cylinders is 152. What is the potential energy stored in this capacitor when a potential difference 8 is applied between the inner and outer cylinder? (=) 8.510-7 J 7.510-6 J 2.010-7 J 1.410-7 J 9.610-7 J

Question

Sariah Hammond

Physics

17 August, 17:34

A cylindrical capacitor is made of two thin-walled concentric cylinders. The inner cylinder has radius 8 mm, and the outer one a radius 11 mm. The common length of the cylinders is 152 m. What is the potential energy stored in this capacitor when a potential difference 8 V is applied between the inner and outer cylinder? (k = 1/4∗π∗ϵ0=8.99109N⋅m2/C2) A cylindrical capacitor is made of two thin-walled concentric cylinders. The inner cylinder has radius 8, and the outer one a radius 11. The common length of the cylinders is 152. What is the potential energy stored in this capacitor when a potential difference 8 is applied between the inner and outer cylinder? (=) 8.510-7 J 7.510-6 J 2.010-7 J 1.410-7 J 9.610-7 J

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Answers (1)

Know the Answer?

Derick Hughes · Answer 1

So the answer is the first one

E = 8.5 x 10 ⁻⁷ J

Explanation:

Given:

r₁ = 8 mm, r₂ = 11 mm, h = 152 m

ε₀ = 8.85 x 10⁻¹² N * m² / C²

C = Q / V

C = 2π * h * ε₀ / ln (r₂ / r₁)

C = [ 2π * 152 m * 8.85 x 10⁻¹² N * m² / C² ] / [ ln (11 mm / 8mm) ]

C = 2.654 x 10⁻⁸ F

C = 26.54 nF

Now to determine the energy Emf

E = ¹/₂ * C * V²

E = ¹/₂ * 26.54 nF * 8²V

E = 8.5 x 10 ⁻⁷ J