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19 November, 18:10

20 kg object travels 28 meter and stops. coefficient friction = 0.085 how much work was done by friction?

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  1. 19 November, 18:32
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    Assuming it is on a horizontal surface:

    friction = μR

    R = 20g (g is gravity 9.81)

    so Friction = 0.085 x 20g

    Work done is force x distance

    so Work done = 0.085 x 20g x 28

    = 466.956 J
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