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23 November, 12:41

An 80.0-gram sample of a gas was heated from 25 °C to 225 °C. During this process 346 J of work was done by the system (which was stationary), and its internal energy increased by 7765 J. What is the specific heat capacity of the gas?

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  1. 23 November, 12:46
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    Step 1: calculate q (charge)

    delta U is change in internal energy

    Using the formula:

    delta U = q + w

    q = delta U - w

    = 6865 J - (-346 J)

    = 7211 J = 7.211 KJ

    q = mc x delta T

    Step 2) Calculate C.

    7211 J = 80.0 g x c x (225-25) °C

    c = 0.451 J / g °C
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