Haley was jumping on the trampoline at her house. As her socks rubbed against the trampoline, they became charged. If a small piece of lint with a charge of + 4.55 E - 21 C is attracted to the socks by a force of 1.5 E - 9 N, what is the magnitude of the electric field at this location?

Question

Drake Stevens

Physics

17 January, 22:12

Haley was jumping on the trampoline at her house. As her socks rubbed against the trampoline, they became charged. If a small piece of lint with a charge of + 4.55 E - 21 C is attracted to the socks by a force of 1.5 E - 9 N, what is the magnitude of the electric field at this location?

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Answers (1)

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Stanley Banks · Answer 1

The magnitude of the electric field (E) at a certain location is calculated by dividing the force (F) by the charge (C). Mathematically,

E = F / C

E = (1.5 x 10^-9 N) / (4.55 x 10^-21 C)

E = 3.30 x 10^11 N/C

Therefore, the magnitude of the electric field is equal to 3.30 x 10^11 N/C.