A pitcher threw a baseball straight up at 35.8 meters per second. what is the ball's velocity after 2.50 seconds?

Question

Malia Duncan

Physics

27 July, 22:14

A pitcher threw a baseball straight up at 35.8 meters per second. what is the ball's velocity after 2.50 seconds?

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Heath · Answer 1

Ok the velocity of an object in free fall is given by the equation:

v=v0-gt, where v0 is the original velocity, g is the gravitational constant (9.8 m/s^2) and t is the time.

so, we substitute values into this equation. v=35.8-9.8*2.5; v=11.3 m/s