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24 March, 21:17

A spring has a spring constant of 30000 N/m. How far must it be stretched (in meters) for its potential energy to be 47 J?

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  1. 24 March, 21:20
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    The elastic potential energy in a spring is given by:

    EPE = 1/2 kx²

    x = √ (2 x 47 / 30,000)

    x = 0.056 m
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