A 10-ft ladder is leaning against a wall. If the top of the ladder slides down the wall at a rate of 2 ft/sec, how fast is the bottom moving along the ground when the bottom of the ladder is 5 ft from the wall

Answer: The bottom of the ladder is moving at 3.464ft/sec

Explanation:

The question defines a right angle triangle. Therefore using pythagorean

h^2 + l^2 = 10^2 = 100 ... eq1

dh/dt = - 2ft/sec

dl / dt = ?

Taking derivatives of time in eq 1 on both sides

2hdh/dt + 2ldl/dt = 0 ... eq2

Putting l = 5ft in eq2

h^ + 5^2 = 100

h^2 = 25 = 100

h Sqrt (75)

h = 8.66 ft

Put h = 8.66ft in eq2

2 * 8.66 * (-2) + 2 * 5 dl/dt

dl/dt = 17.32 / 5

dl/dt = 3.464ft/sec