An object has a starting velocity of 20 m/s. If it accelerates at a rate of 2 m/s' for 3 seconds,

Calcutate its final velocity.

Calculate its displacement

26 m/s

69 m

Explanation:

Given:

v₀ = 20 m/s

a = 2 m/s²

t = 3 s

Find: v and Δx

v = at + v₀

v = (2 m/s²) (3 s) + 20 m/s

v = 26 m/s

Δx = v₀ t + ½ at²

Δx = (20 m/s) (3 s) + ½ (2 m/s²) (3 s) ²

Δx = 69 m