A 76 kg climber climbs to the top of Mount Everest, which has a peak height of 8850 m above sea level. What is the climber's potential energy with respect to sea level?

Ep=Potential Energy

m=mass=76 Kg

g=gravitational Field Strength=9,8 m/s²

h=vertical height=8850 m

Ep=m*g*h

Ep = (76 Kg) * (9,8 m/s²) * (8850 m) = 6591480 Joules.

Solution: 6591480 Joules.