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24 February, 01:23

Using the Bohr model, what is the ratio of the energy of the nth orbit of a triply ionized beryllium atom (Be3+, Z = 4) to the energy of the nth orbit of a hydrogen atom (H) ? Enth orbit, Be / Enth orbit, H

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  1. 24 February, 01:42
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    16

    Explanation:

    solution:

    by taking the ratio of the energy E_n, be of the nth orbit of a beryllium atom

    Z_be=4 to the energy E_n, h of the nth orbit of a hydrogen (Z_h=1) atom gives

    E_n, B/E_n, H = - (2.18*10^-18) * Z^2_BE / - (2.18*10^-18) * Zh^2/n^2

    =Z^2_BE+/Z^2_H

    = (4) ^2 / (1) ^2

    = 16
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