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14 August, 18:25

Suppose a rock is dropped off a cliff with an initial speed of 0m/s. What is the rocks speed after 5 secounds, in m/s, if it encounters no air resistance?

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Answers (2)
  1. 14 August, 18:41
    0
    50 m/s

    Explanation:

    u = 0 m/s, t = 5 seconds, v = ?, g = 10 m/s^2

    Use first equation of motion

    v = u + g t

    v = 0 + 10 x 5 = 50 m/s
  2. 14 August, 18:52
    0
    The rock's speed after 5 seconds is 98 m/s.

    Explanation:

    A rock is dropped off a cliff.

    It had an initial velocity of 0 m/s. And now it is moving downwards under the influence of gravitational force with the gravitational acceleration of 9.8 m/s².

    Speed after 5 seconds = V

    We know that acceleration = average speed/time

    In our case,

    g = ((0+V) / 2) / 5

    9.8*5 = V/2

    => V = 2*9.8*5

    V = 98 m/s
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