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19 November, 05:25

In a 400-m relay race the anchorman (the person who runs the last 100 m) for team A can run 100 m in 9.8 s. His rival, the anchorman for team B, can cover 100 m in 10.1 s. What is the largest lead the team B runner can have when the team A runner starts the final leg of the race, in order that the team A runner not lose the race?

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  1. 19 November, 05:43
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    largest lead = 3 m

    Explanation:

    Basically, this problem is about what is the largest possible distance anchorman for team B can have over the anchorman for team A when the final leg started that anchorman for team A won the race. This show that anchorman for team A must have higher velocity than anchorman for team B to won the race as at the starting of final leg team B runner leads the team A runner.

    So, first we need to calculate the velocities of both the anchorman

    given dа ta:

    Distance = d = 100 m

    Time arrival for A = 9.8 s

    Time arrival for B = 10.1 s

    Velocity of anchorman A = D / Time arrival for A

    =100 / 9.8 = 10.2 m/s

    Velocity of anchorman B = D / Time arrival for B

    =100/10.1 = 9.9 m/s

    As speed of anchorman A is greater than anchorman B. So, anchorman A complete the race first than anchorman B. So, anchorman B covered lower distance than anchorman A. So to calculate the covered distance during time 9.8 s for B runner, we use

    d = vt

    = 9.9 x 9.8 = 97 m

    So, during the same time interval, anchorman A covered 100 m distance which is greater than anchorman B distance which is 97 m.

    largest lead = 100 - 97 = 3 m

    So if his lead no more than 3 m anchorman A win the race.
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