A plant box falls from the windowsill 25.0 m above the sidewalk and hits the cement 3.0 s later. What is the box's velocity when it hits the ground?

Velocity of the box when it hits the ground=22.14 m/s

Explanation:

using kinematic equation

Vf² = Vi² + 2 g h

Vf = final velocity

Vi = initial velocity=0

g = 9.8 m/s²

h = height = 25 m

so Vf² = 0 + 2 (9.8) (25)

Vf=22.14 m/s

Thus the velocity of the box when it hits the ground=22.14 m/s