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11 May, 11:23

Suppose that at room temperature, a certain aluminum bar is 1.0000 m long. The bar gets longer when its temperature is raised. The length l of the bar obeys the following relation: l=1.0000+2.4*10-5T, where T is the number of degrees Celsius above room temperature. What is the change of the bar's length if the temperature is raised to 11.3 ∘C above room temperature?

Express your answer in meters to two significant figures.

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  1. 11 May, 11:50
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    The length of the bar is 31.5m,

    keeping in mind the relation that is obeyed:

    l=1.000+2.4*10-5T

    reverse the equation to avoid confusion

    T5-10*2.4+1.0000=l

    now follow P. E. M. D. A. S

    because there are no perenthesis or exponents you can eliminate the P and E.

    start by multiplying 11.3 by 5

    (11.3*5=56.5)

    now the equation will read

    56.5-10*2.4+1.0000

    then multiply 10 by 2.4

    (10*2.4=24)

    equation reads

    56.5-24+1.0000

    now that we have the solved all of the multiplication we can move on with p. e. m. D. A. S.

    since there is no division to solve we can start the addition

    the equation should look like this:

    56.5-24+1.0000

    now add 24 to 1.0000

    (24+1.0000=25)

    equation after findin the sum of the addition solved is:

    56.5-25=l

    finally subtract 25 from 56.5

    (56.5-25=31.5)

    31.5=l
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