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24 November, 14:00

g A 4 cm diameter "bobber" with a mass of 3 grams floats on a pond. A thin, light fishing line is tied to the bottom of the bobber, and from the bottom hangs a 10 gram lead weight. The density of lead is 11.3 g/cm3. What fraction of the bobber's volume is submerged, as a percent of the total volume

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  1. 24 November, 14:02
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    total weight acting downwards

    = 3g + 10g

    13 g

    volume of lead = 10 / 11.3 =.885 cm³

    Let the volume of bobber submerged in water be v in floating position. buoyant force on bobber = v x 1 x g

    Buoyant force on lead =.885 x 1 x g

    total buoyant force = vg +.885 g

    For floating

    vg +.885 g = 13 g

    v = 12.115 cm³

    total volume of bobber

    = 4/3 x 3.14 x 2³

    = 33.5 cm³

    fraction of volume submerged

    = 12.115 / 33.5

    =.36

    = 36 %
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