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8 August, 09:53

A boy in a pedal car is moving at a speed of 1.40 m/s at the start of a 2.00 m high and 12.4 m long incline. The total mass is 45.5 kg, air resistance and rolling resistance can be modeled as a constant friction force of 41.0 N, and the speed at the lower end of the incline is 6.90 m/s. Determine the work done (in J) by the boy as the car travels down the incline.

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  1. 8 August, 10:21
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    W = 655J

    Explanation:

    Workdone = change in kinetic energy + change in potential energy - workdone against friction

    = 1/2m (v2²-v1²) + mg (h2 - h1) + Ff*d

    Given

    m = 45.5kg

    v1 = 1.40m/s

    v2 = 6.90m/s

    h1 = 2.00m

    h2 = 0m (bottom of the incline)

    Ff = 41N frictional force

    d = 12.4m

    Workdone = 1/2*45.5 * (6.90²-1.40²) + mg (0 - 2.00) + 41*12.4

    Workdone = 655J

    Ff * d = work done against friction.
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