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31 May, 12:24

A cube of ice is taken from the freezer at - 5.5 ∘C and placed in a 75-g aluminum calorimeter filled with 300 g of water at room temperature of 20.0 ∘C. The final situation is observed to be all water at 17.0 ∘C. The specific heat of ice is 2100 J/kg⋅C∘, the specific heat of aluminum is 900 J/kg⋅C∘, the specific heat of water is is 4186 J/kg⋅C∘, the heat of fusion of water is 333 kJ/Kg.

What was the mass of the ice cube? Express your answer to two significant figures and include the appropriate units.

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  1. 31 May, 12:46
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    Let mass of ice cube taken out be m kg.

    ice will gain heat to raise its temperature from - 5.5° to 0° and then from 0° to 17°.

    Total heat gained = m x 2.1 x 5.5 + m x 333 + m x 4.186 x 17

    = (11.55 + 333 + 71.162) m

    = 415.712 m kJ

    Heat lost by aluminium calorimeter

    =.075 x. 9 x 3

    =.2025 kJ

    Heat lost by water

    =.3 x 4.186 x 3

    = 3.7674

    Total heat lost

    = 3.9699 kJ

    Heat lost = heat gained

    415.712 m = 3.9699

    m =.0095 kg

    9.5 gm.
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