A certain metal with atomic mass 2.9 * 10-25 kg has an interatomic bond with length 2.3 * 10-10 m and stiffness 48 N/m. What is the speed of sound in a rod made of this metal?

Speed of sound = 2958.88m/s

Explanation:

The speed of sound is given by:

V = Sqrt (s/m) * d

Where a = stiffness of the metal

m = atomic mass of the metal

d, = distance

Given:

s = 48N/m

d = 2.3*10^-10m

m = 2.9*10^-25kg

V = Sqrt (48 / (2.9*10^-25) * 2.3 * 10^-10

V = Sqrt (1.655*10^26) * 2.3*10^-10

V = 1.286*10^13 * 2.3*10^-10

V = 2958.88m/s