A scalloped hammerhead shark swims at a steady speed of 1.5 m/s with its 88 cm - cm-wide head perpendicular to the earth's 56 μT magnetic field. What is the magnitude of the emf induced between the two sides of the shark's head? Express your answer using two significant figures.

Question

Tucker

Physics

8 January, 05:48

A scalloped hammerhead shark swims at a steady speed of 1.5 m/s with its 88 cm - cm-wide head perpendicular to the earth's 56 μT magnetic field. What is the magnitude of the emf induced between the two sides of the shark's head? Express your answer using two significant figures.

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Answers (1)

Know the Answer?

Diya Stanton · Answer 1

7.4 x 10⁻⁵ T.

Explanation:

Emf induced = BLv

Where B is magnetic field, L is length of rod or any other object moving in magnetic field and v is velocity of moving rod.

Here B = 56 x 10⁻⁶ T

L = 88 X 10⁻² m

v = 1.5 m/s

emf induced = 56 x 10⁻⁶ x 88 x 10⁻² x 1.5

= 7.4 x 10⁻⁵ T.