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21 October, 13:24

An object is dropped from rest from a height of 4.1 107 m above the surface of the Earth. If there is no air resistance, what is its speed when it strikes the Earth

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  1. 21 October, 13:29
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    2.83 x 10^4m/s

    Explanation:

    First, let us calculate the time taken by the object to hit the surface of the earth.

    H = 4.1 x 10^7m

    g = 9.8m/s2

    t = √ (2H/g)

    t = √ ((2x 4.1 x 10^7) / 9.8)

    t = 2892.64secs

    Now, we can find the velocity with which the object strikes the earth as follows:

    V = gt

    V = 9.8 x 2892.64

    V = 2.83 x 10^4m/s
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