A block of ice with mass mA rests on a wedge of ice with mass mB=7.93 kg that is cut so that the surface of the wedge makes an angle of 37.5 with the ground. There is no friction between the pieces of ice or between the ice and the ground. At time t=0 the blocks are released from rest. What is the acceleration of mA in the direction parallel to the ground.

Question

Aron Duarte

Physics

3 February, 20:38

A block of ice with mass mA rests on a wedge of ice with mass mB=7.93 kg that is cut so that the surface of the wedge makes an angle of 37.5 with the ground. There is no friction between the pieces of ice or between the ice and the ground. At time t=0 the blocks are released from rest. What is the acceleration of mA in the direction parallel to the ground.

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Answers (1)

Know the Answer?

Amiya Patterson · Answer 1

The answer is 7.52 m/s².

Explanation:

To determine acceleration, N = Ma*g : cos Ф

N sin Ф = ma

a = g Tan Ф m/s²

g = 9.8 m/s² and Ф = 37.5° (angle for the velocity and gravitational force)

so, a = 9.8 * tan (37.5°)

Acceleration has to be determined in order to get the final answer.

a = 7.5198 m/s²