Ask Question
24 March, 06:22

0.10-kilogram model rocket's engine is designed to deliver an impulse of 6.0 newton-seconds. If the rocket engine burns for 0.75 second, what average force does it produce?

+4
Answers (1)
  1. 24 March, 06:46
    0
    8.0 N

    Explanation:

    Force: This can be defined as the mass of a body and its acceleration. The S. I unit of Force is Newton (N).

    Mathematically, Fore is expressed as

    F = ma ... equation 1

    Where F = force, m = mass, a = acceleration.

    and

    I = mΔv

    Δv = I/m ... Equation 2

    Where I = impulse, m = mass, Δv = change in velocity

    Given: I = 6.0 Newton-seconds, m = 0.1 kilogram.

    Substituting into equation 2

    Δv = 6.0/0.1

    Δv = 60 m/s.

    But

    a = Δv/t

    where t = time = 0.75 seconds.

    a = 60/0.75

    a = 80 m/s²

    Substitute the values of a and m into equation 1.

    F = 0.1 (80)

    F = 8.0 N.

    Thus the average force produced = 8.0 N
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “0.10-kilogram model rocket's engine is designed to deliver an impulse of 6.0 newton-seconds. If the rocket engine burns for 0.75 second, ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers