Ask Question
6 July, 19:12

One watt (w) is equal to 1 j/s. assuming that 5.0% of the energy output of a 75 w light bulb is visible light and that the average wavelength of the visible light is 550 nm, how many photons are emitted by the light bulb per second?

+4
Answers (1)
  1. 6 July, 19:25
    0
    Ephoton = hc/λ = 6.63E-34Js x 3.00E8m/s / 550E-9m = 3.61E-19J 0.05 x 75J/s x 1s = 3.75J 3.75J x 1photon / 3.61E-19J = 1.04E19 photons.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “One watt (w) is equal to 1 j/s. assuming that 5.0% of the energy output of a 75 w light bulb is visible light and that the average ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers