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17 November, 22:06

A 0.50 kg croquet ball is initially at rest on the grass. When theball is struck by a mallet, the average force exerted on it is240 N. If the ball's speed after beingstruck is 3.0 m/s, how long was the malletin contact with the ball?

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  1. 17 November, 22:25
    0
    time=6.25*10⁻³ seconds

    or

    time=6.25 Milliseconds

    Explanation:

    Given Data

    Ball mass = 0.50 kg

    Force = 240 N

    Speed = 3.0 m/s

    To find

    Time

    Solution

    From Newtons second Law of motion

    Force=mass*acceleration

    As mass and Force is given we need to Find acceleration

    So

    Acceleration=Force/mass

    Acceleration=240/0.50

    Acceleration=480 m/s²

    When ball was at rest its velocity at that time was 0. Now the final velocity is given as:

    Velocity=acceleration*time

    As we have find the acceleration and velocity is given so we can find time easily

    So

    time=velocity/acceleration

    time = (3.0m/s) / 480 N

    time=6.25*10⁻³ seconds

    or

    time=6.25 Milliseconds
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