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11 May, 09:36

A diver initially moving horizontally with speed v dives dives offthe edge of a vertical cliff and lands in the water a distance dfrom the base of the cliff. How far from the base of the cliffwould the diver have landed if the diver initially had been movinghorizontally with speed 2v?

A. d

B. √ (2d)

C. 2d

D. 4d

E. It cannot be determined unless the hieght of the cliff isknown

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Answers (1)
  1. 11 May, 09:49
    0
    Option C is correct

    Explanation:

    "The time is determined by the vertical distance. The formula is sqr (2d/a) = t. There still is no acceleration in the horizontal direction."

    For the first drive

    d = d

    t = sqr (2d/a)

    r = v

    For the Second drive

    d = ?

    t = sqr (2d/a)

    r = 2v

    Since the times are same, equate the results.

    t = d/v = d1/2v

    v*d1 = 2v*d The v's cancel because they are related.

    d1 = 2d.

    You go twice as far as you did before.

    Option C is correct
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