A flask containing argon gas is connected to an closed-ended mercury manometer. The closed end is under vacuum. If the mercury level in the closed arm is 230. mm above that in the arm connected to the flask, what is the argon pressure, in torr?

230 torr

Explanation:

Given that

P = 230 mm of Hg

If argon gas and mercury is in equilibrium position then the pressure on the both side will be same.

As we know that

1 torr = 1 mm of Hg

So the pressure of the argon will be 230 torr.

Unit conversion

1 torr = 1 mm of Hg

1 bar = 100 KPa = 10⁵ Pa = 10⁵ N/m² = 0.1 MPa = 0.1 x 10⁶ Pa