A 12 n cart is moving on a horizontal surface with a coefficient of kinetic friction of 0.20. what force of friction must be overcome to keep the object moving at a constant velocity?

We must remember that the total net force equation at constant velocity is:

F - Ff = 0

of

F - µN = 0

Using Newton's 2nd Law of Motion:

F = m a

Where,

F = net force acting on the body

m = mass of the body

a = acceleration of the body

Since the cart is moving at a constant velocity, then acceleration is zero, hence the working equation simplifies to

F = net Force = 0

Therefore,

F - µN = 0

where

µ = coefficient of friction = 0.20

N = normal force acting on the cart = 12 N

Therefore,

F - 0.20 (12) = 0

F = 2.4 N